19x^2-12x-7=0

Solution for 19x^2-12x-7=0 equation:

19x^2-12x-7=0

a = 19; b = -12; c = -7;
Δ = b2-4ac
Δ = -122-4·19·(-7)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-26}{2*19}=\frac{-14}{38}
=-7/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+26}{2*19}=\frac{38}{38}
=1
$